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The energy needed to heat up a substance is given by the formula shown here:

 

ΔQ=m.c.ΔΘ    or    ΔE=m.c.ΔΘ

change in thermal energy = mass x specific heat capacity x temperature change

1. This formula should be used when a substance is...

  • A. melting
  • B. boiling
  • C. heated but staying in the same state.
  • D. staying at the same temperature.

2+3. The image shows a large glass vase holding 2 kg of cold water.

Water has a specific heat capacity (c) of 4200 J / Kg 0C.

2. The energy needed to heat 2 kg of water by 5 0C is ..

  • A. 4200 J
  • B. 8400 J
  • C. 42000 J
  • D. 84000 J

3. If I supply 210 kJ of heat to the same 2 kg of water, how much would the temperature increase?

  • A. 25 0C
  • B. 50 0C
  • C. 100 0C
  • D. 250 0C

Q 4-6. These questions are about heating different bars of copper.

Copper has a specific heat capacity of 800 J / Kg 0C.

What are the missing values?

copper bar
 

Energy Supplied

Mass (kg)
Temperature Increase (0C)
4.
20
10
5. 8000 J
20
6.
400 kJ
5

 

 

7. Specific Latent Heat is the energy needed for 1 kg of substance to change state.

Which of these correctly identifies the change of state?

Q=mL   or    E=mL

Energy for change in state = mass x specific latent heat

 

Latent Heat of Fusion Latent Heat of Vaporisation
A
Solid to Liquid Solid to Gas
B
Liquid to Gas Solid to Gas
C
Liquid to Gas Solid to Liquid
D
Solid to Liquid Liquid to Gas

8. These ice cubes have a total mass of 100g. The specific latent heat needed to make them change state is 330 kJ / kg.

What is the energy needed to make them melt from ice at 0 0C to water at 0 0C?

ice cubes
Howard wang86 wikimedia commons
  • A. 33000 kJ
  • B. 3300 kJ
  • C. 33 kJ
  • D. 3.3 kJ

9. If I supply 1 MJ of energy, roughly how much mass of ice cubes could I melt? (Again all at the melting point - 0 0C).

  • A. 30 kg
  • B. 3 kg
  • C. 0.3 kg
  • D. 0.03 kg

10. When the ice cubes are first taken out of the freezer they are really cold. Which graph best shows the change in temperature as the ice cubes eventually melt and continue to warm up?

 

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Question 1:

The formula

Q=mcΔT

is used to calculate the heat transferred when a substance changes temperature (i.e., its temperature increases or decreases), without changing state.

So it applies when a substance is heated but staying in the same state (solid, liquid, or gas).

Correct answer: C. heated but staying in the same state.


*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
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Question 2:

We use the formula:

Q=mcΔT

Given:
m=2 kg
c=4200 J/kg°C
ΔT=5 °C

Q=2×4200×5

Q=42000 J

Correct answer: C. 42000 J.


*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
Grade Gorilla uses Gemini, Deepseek and a range of other A.I. chatbots to generate the saved responses. Some answers have had human intervention for clarity or where the A.I. has not been able to answer the question.

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Question 3:

We use the same formula:

Q=mcΔT

Given:
Q=210 kJ = 210,000 J
m=2 kg
c=4200 J/kg°C

210,000=2×4200×ΔT

ΔT=210,000/8400=25 °C

Correct answer: A. 25 °C.


*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
Grade Gorilla uses Gemini, Deepseek and a range of other A.I. chatbots to generate the saved responses. Some answers have had human intervention for clarity or where the A.I. has not been able to answer the question.

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Question 4:

We have three rows with missing values. Use Q = m * c * ΔT, c=800 J/(kg°C).

Energy supplied = ? , m=20 kg, ΔT=10°C. So Q = 20 * 800 * 10 = 20*8000 = 160,000 J = 160 kJ.


*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
Grade Gorilla uses Gemini, Deepseek and a range of other A.I. chatbots to generate the saved responses. Some answers have had human intervention for clarity or where the A.I. has not been able to answer the question.

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Question 5:

We have three rows with missing values. Use Q = m * c * ΔT, c=800 J/(kg°C).

Q=8000 J, m=?, ΔT=20°C. So m = Q/(cΔT)=8000/(800*20)=8000/16000=0.5 kg.


*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
Grade Gorilla uses Gemini, Deepseek and a range of other A.I. chatbots to generate the saved responses. Some answers have had human intervention for clarity or where the A.I. has not been able to answer the question.

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Question 6:

We have three rows with missing values. Use Q = m * c * ΔT, c=800 J/(kg°C).

Q=400 kJ = 400,000 J, m=5 kg, ΔT=?. So ΔT = Q/(m*c)=400000/(5*800)=400000/4000=100°C.


*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
Grade Gorilla uses Gemini, Deepseek and a range of other A.I. chatbots to generate the saved responses. Some answers have had human intervention for clarity or where the A.I. has not been able to answer the question.

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Question 7:

We need to identify which option correctly matches the terms "Latent Heat of Fusion" and "Latent Heat of Vaporisation" with the correct change of state.

Now check the options:

A: Solid to Liquid (fusion), Solid to Gas (vaporisation) – incorrect, vaporisation is liquid to gas, not solid to gas (that's sublimation).

B: Liquid to Gas (fusion? No, that's vaporisation), Solid to Gas (vaporisation? No) – incorrect.

C: Liquid to Gas (fusion? No), Solid to Liquid (vaporisation? No) – incorrect.

D: Solid to Liquid (fusion), Liquid to Gas (vaporisation) – correct.

Thus answer is D.


*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
Grade Gorilla uses Gemini, Deepseek and a range of other A.I. chatbots to generate the saved responses. Some answers have had human intervention for clarity or where the A.I. has not been able to answer the question.

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Question 8:

We use the formula for latent heat:

Q=mL

where m=100 g=0.1 kg and L=330 kJ/kg.

Q=0.1×330=33 kJ

Correct answer: C. 33 kJ.


*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
Grade Gorilla uses Gemini, Deepseek and a range of other A.I. chatbots to generate the saved responses. Some answers have had human intervention for clarity or where the A.I. has not been able to answer the question.

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Question 9:

We use Q=mL, so m=Q/L.

Given:
Q=1 MJ=1,000,000 J
L=330 kJ/kg=330,000 J/kg

m=1,000,000/330,000≈3.03 kg

Roughly 3 kg → option B.


*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
Grade Gorilla uses Gemini, Deepseek and a range of other A.I. chatbots to generate the saved responses. Some answers have had human intervention for clarity or where the A.I. has not been able to answer the question.

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Question 10:

The graph of temperature vs. time for ice taken from a freezer (below 0 °C), then warmed until it melts and continues to warm as water, has three distinct sections:

  1. Initial rise (solid ice heating) – diagonal line sloping upward until it reaches 0 °C.

  2. Flat plateau (melting) – horizontal line at 0 °C while the ice absorbs latent heat without temperature change.

  3. Final rise (liquid water heating) – diagonal line sloping upward again, starting at 0 °C and increasing.

So the shape is best described as:
A line that rises, then flattens, then rises again

This matches graph C.


*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
Grade Gorilla uses Gemini, Deepseek and a range of other A.I. chatbots to generate the saved responses. Some answers have had human intervention for clarity or where the A.I. has not been able to answer the question.