Question 1:

Let’s go through each option:

A. There is a weak attractive force between the molecules
In an ideal gas, it is assumed that there are no intermolecular forces. So weak attractive forces are not a characteristic of an ideal gas — this statement is false for an ideal gas.

B. Gas molecules occupy a negligible volume
This is true for an ideal gas (point particles).

C. Gas molecules are in random motion
This is true for an ideal gas (kinetic theory).

D. Only elastic collisions occur between molecules
This is true for an ideal gas (kinetic energy conserved in collisions).

Thus, the one that is NOT a characteristic is A.

*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
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Question 2:

The relationship between the pressure and volume of a fixed mass of an ideal gas at a constant temperature is described by Boyle's Law.

According to Boyle's Law, pressure is inversely proportional to volume. This means as the volume of the gas increases, its pressure decreases, and vice versa.

The graph that best represents this relationship is a downward-sloping curve (a hyperbola) when pressure (P) is plotted against volume (V). The equation for this relationship is PV=k, where k is a constant.

This is shown by graph A.

*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
Grade Gorilla uses Gemini, Deepseek and a range of other A.I. chatbots to generate the saved responses. Some answers have had human intervention for clarity or where the A.I. has not been able to answer the question.

Question 3:

For an ideal gas, we assume:

• No intermolecular forces.

• Molecules have negligible volume.

Real gases deviate from ideal behavior when:

1. Pressure is high → molecules are forced closer together, so the volume of molecules is no longer negligible.

2. Temperature is low → molecules have less kinetic energy, so intermolecular attractions become significant.

Thus, the greatest deviation occurs at low temperature and high pressure.

*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
Grade Gorilla uses Gemini, Deepseek and a range of other A.I. chatbots to generate the saved responses. Some answers have had human intervention for clarity or where the A.I. has not been able to answer the question.

Question 4:

We use the ideal gas law:

Here, n n and R R are constant.

Initially: P₁V₁=nRT₁

After changes:

• Volume doubled → V₂=2V₁

• Temperature doubled (in K) → T₂=2T₁

New equation:

But nRT₁=P₁V₁​ , so:

Divide both sides by 2V₁​ :

So the pressure remains the same. This corresponds to answer A.

*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
Grade Gorilla uses Gemini, Deepseek and a range of other A.I. chatbots to generate the saved responses. Some answers have had human intervention for clarity or where the A.I. has not been able to answer the question.

Question 5:

We can solve this using Charles’s law:

where temperature is in kelvin.

Step 1: Convert given temperature to Kelvin

Step 2: Solve for T₂:

40/300=80/T₂

So T₂=80 × 300/40 = 80 × 7.5 = 600 K

Step 3: Convert T2 T 2​  back to °C

Step 4: Match with options

*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
Grade Gorilla uses Gemini, Deepseek and a range of other A.I. chatbots to generate the saved responses. Some answers have had human intervention for clarity or where the A.I. has not been able to answer the question.

Question 6:

We can use the combined gas law:

Step 1: Identify given values

• V1=100 cm³

• P₂=½P₁

• T₂=½T₁

• V₂=?

Step 2: Substitute into the equation

Step 3: Simplify the right-hand side

P₁⋅100/T₁= (½/½)P₁⋅V₂ /T₁ = P₁⋅V₂ /T₁

Step 4: Equate both sides

Cancel P₁/T₁from both sides:

Step 5: Conclusion

The new volume is 100 cm³. Answer B.

*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
Grade Gorilla uses Gemini, Deepseek and a range of other A.I. chatbots to generate the saved responses. Some answers have had human intervention for clarity or where the A.I. has not been able to answer the question.

Question 7:

The graph that represents the relationship between the volume and the temperature in kelvin of a fixed mass of an ideal gas at constant pressure is a straight line passing through the origin of the Kelvin temperature scale.

This relationship is described by Charles's Law.

Charles's Law Explained
Charles's Law states that for a fixed mass of an ideal gas at constant pressure, the volume (V) is directly proportional to its absolute temperature (T).

Mathematically:

V∝T or V = kT
​
=k(where k is a constant)
If you plot Volume (y-axis) against Temperature (x-axis):

Using the Kelvin Scale (Absolute Temperature): The graph is a straight line that passes through the origin (0,0), demonstrating the direct proportionality. At 0 K, the theoretical volume of the gas is zero.

Using the Celsius Scale: The graph is still a straight line, but it does not pass through the origin. Instead, the line extrapolates (extends backward) to the x-axis (zero volume) at a temperature of −273.15 °C (Absolute Zero).

Since the question asks for the temperature in °C, the correct graph is a straight line that, when extrapolated, intersects the x-axis at −273.15 °C.

*The line will therefore be straight, but have a positive value at 0°C. This corresponds to graph C.
The Silverback (edit )

*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
Grade Gorilla uses Gemini, Deepseek and a range of other A.I. chatbots to generate the saved responses. Some answers have had human intervention for clarity or where the A.I. has not been able to answer the question.

Question 8:

We use the ideal gas law:

Step 1: Convert units to match R (8.31 J K⁻¹ mol⁻¹)

• Pressure P=100 kPa=1.0×10⁵ Pa

• Volume V=2000 cm³= 2.0×10⁻³ m³

• Temperature T=400 K

Step 2: Solve for n

Substitute:

Step 3: Match with given options

B: 100 x 2 is the same as our (1.0×10⁵)×(2.0×10⁻³)

That’s correct.

* The Silverback (edit - removed the other options which are incorrect, for brevity)

*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
Grade Gorilla uses Gemini, Deepseek and a range of other A.I. chatbots to generate the saved responses. Some answers have had human intervention for clarity or where the A.I. has not been able to answer the question.

Question 9:

We use the combined gas law:

Step 1: Identify given values

• P1=4 kPa

• V₂=½V₁

• T₂=2T₁

• P₂=?

Step 2: Substitute into the equation

Step 3: Simplify the right-hand side

So:

Step 4: Cancel V₁/T₁from both sides

Step 5: Conclusion

The new pressure is 16 kPa

*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
Grade Gorilla uses Gemini, Deepseek and a range of other A.I. chatbots to generate the saved responses. Some answers have had human intervention for clarity or where the A.I. has not been able to answer the question.

Question 10:

We use the ideal gas law:

where n=m/M, with m= mass, M = molar mass.

So:

Step 1: Identify given values in correct units

• m=2.00 g

• V=500 cm³=5.00×10^-4 m³

• T=24.85∘C=24.85+273.15≈298 K

• P=1.01×10⁵ Pa

• R=8.31 J K⁻¹mol⁻¹

Step 2: Write expression for M

M=mRT / PV

Step 3: Match with options

That matches C exactly:

*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
Grade Gorilla uses Gemini, Deepseek and a range of other A.I. chatbots to generate the saved responses. Some answers have had human intervention for clarity or where the A.I. has not been able to answer the question.